Question

What is the area of the parabola $${x^2} = y$$  bounded by the line $$y = 1\,?$$

A. $$\frac{1}{3}$$ square unit
B. $$\frac{2}{3}$$ square unit
C. $$\frac{4}{3}$$ square units  
D. $$2$$ square units
Answer :   $$\frac{4}{3}$$ square units
Solution :
Application of Integration mcq solution image
Area of $$ABCD = 2 \times 1 = 2\,{\text{sq}}{\text{. units}}$$
Area of $$BAODC = \int_{ - 1}^1 {{x^2}dx} = \left. {\frac{{{x^3}}}{3}} \right|_{ - 1}^1 = \frac{2}{3}\,{\text{sq}}{\text{. units}}$$
Required area $$ = 2 - \frac{2}{3} = \frac{4}{3}{\text{ sq}}{\text{. units}}$$

Releted MCQ Question on
Calculus >> Application of Integration

Releted Question 1

The area bounded by the curves $$y = f\left( x \right),$$   the $$x$$-axis and the ordinates $$x = 1$$  and $$x = b$$  is $$\left( {b - 1} \right)\sin \left( {3b + 4} \right).$$     Then $$f\left( x \right)$$  is-

A. $$\left( {x - 1} \right)\cos \left( {3x + 4} \right)$$
B. $$\sin \,\left( {3x + 4} \right)$$
C. $$\sin \,\left( {3x + 4} \right) + 3\left( {x - 1} \right)\cos \left( {3x + 4} \right)$$
D. none of these
Releted Question 2

The area bounded by the curves $$y = \left| x \right| - 1$$   and $$y = - \left| x \right| + 1$$   is-

A. $$1$$
B. $$2$$
C. $$2\sqrt 2 $$
D. $$4$$
Releted Question 3

The area bounded by the curves $$y = \sqrt x ,\,2y + 3 = x$$    and $$x$$-axis in the 1st quadrant is-

A. $$9$$
B. $$\frac{{27}}{4}$$
C. $$36$$
D. $$18$$
Releted Question 4

The area enclosed between the curves $$y = a{x^2}$$   and $$x = a{y^2}\left( {a > 0} \right)$$    is 1 sq. unit, then the value of $$a$$ is-

A. $$\frac{1}{{\sqrt 3 }}$$
B. $$\frac{1}{2}$$
C. $$1$$
D. $$\frac{1}{3}$$

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