Question
Three identical dice are rolled. The probability that the same number will appear on each of them is
A.
$$\frac{1}{6}$$
B.
$$\frac{1}{36}$$
C.
$$\frac{1}{18}$$
D.
$$\frac{3}{28}$$
Answer :
$$\frac{1}{36}$$
Solution :
Favourable cases $$ = 6;\left\{ {\left( {1,1,1} \right),\left( {2,2,2} \right),.....\left( {6,6,6} \right)} \right\}$$
Total cases $$ = 6 \times 6 \times 6 = 216$$
$$\therefore \,\,{\text{Req}}{\text{. prob}}{\text{. = }}\frac{6}{{216}} = \frac{1}{{36}}$$