Question
The orthocenter of the triangle formed by the lines $$xy = 0$$ and $$x+y=1$$ is-
A.
$$\left( {\frac{1}{2},\,\frac{1}{2}} \right)$$
B.
$$\left( {\frac{1}{3},\,\frac{1}{3}} \right)$$
C.
$$\left( {0,\,0} \right)$$
D.
$$\left( {\frac{1}{4},\,\frac{1}{4}} \right)$$
Answer :
$$\left( {0,\,0} \right)$$
Solution :
The lines by which $$\Delta $$ is formed are $$x = 0, \,y = 0$$ and
$$x+y=1.$$
Clearly, it is right $$\Delta $$ and we know that in a right $$\Delta $$ orthocenter coincides with the vertex at which right $$\angle $$ is formed.
$$\therefore $$ Orthocenter is $$\left( {0,\,0} \right).$$