The locus of the center of a circle which touches the circle $$\left| {z - {z_1}} \right| = a\,\,{\text{and }}\left| {z - {z_2}} \right| = b$$ externally $$\left( {z,{z_1}\& {z_2}\,{\text{are complex numbers}}} \right)$$ will be
A.
an ellipse
B.
a hyperbola
C.
a circle
D.
none of these
Answer :
a hyperbola
Solution :
Let the circle be $$\left| {z - {z_0}} \right| = r.$$ Then according to given conditions $$\left| {{z_0} - {z_1}} \right| = r + a\,\,{\text{and }}\left| {{z_0} - {z_2}} \right| = r + b.$$ Eliminating $$r,$$ we get $$\left| {{z_0} - {z_1}} \right| - \left| {{z_0} - {z_2}} \right| = a - b.$$
∴ Locus of center $${{z_0}}$$ is $$\left| {{z} - {z_1}} \right| - \left| {{z} - {z_2}} \right| = a - b,$$ which represents a hyperbola
Releted MCQ Question on Algebra >> Complex Number
Releted Question 1
If the cube roots of unity are $$1,\omega ,{\omega ^2},$$ then the roots of the equation $${\left( {x - 1} \right)^3} + 8 = 0\,\,{\text{are}}$$