Question

The equation of the common tangent to the equal parabolas $${y^2} = 4ax$$   and $${x^2} = 4ay$$   is :

A. $$x + y + a = 0$$  
B. $$x + y = a$$
C. $$x - y = a$$
D. none of these
Answer :   $$x + y + a = 0$$
Solution :
Any tangent to $${y^2} = 4ax$$   is $$y = mx + \frac{a}{m}.$$   It touches $${x^2} = 4ay$$   if $${x^2} = 4a\left( {mx + \frac{a}{m}} \right),$$     i.e., $${x^2} - 4amx - \frac{{4{a^2}}}{m} = 0$$     has equal roots.
So, $${m^3} + 1 = 0,$$   i.e., $$m = - 1.$$   Hence, the common tangent is $$y = - x - a.$$

Releted MCQ Question on
Geometry >> Parabola

Releted Question 1

Consider a circle with its centre lying on the focus of the parabola $${y^2} = 2px$$   such that it touches the directrix of the parabola. Then a point of intersection of the circle and parabola is-

A. $$\left( {\frac{p}{2},\,p} \right){\text{ or }}\left( {\frac{p}{2},\, - p} \right)$$
B. $$\left( {\frac{p}{2},\, - \frac{p}{2}} \right)$$
C. $$\left( { - \frac{p}{2},\,p} \right)$$
D. $$\left( { - \frac{p}{2},\, - \frac{p}{2}} \right)$$
Releted Question 2

The curve described parametrically by $$x = {t^2} + t + 1,\,\,y = {t^2} - t + 1$$      represents-

A. a pair of straight lines
B. an ellipse
C. a parabola
D. a hyperbola
Releted Question 3

If $$x+y=k$$   is normal to $${y^2} = 12x,$$   then $$k$$ is-

A. $$3$$
B. $$9$$
C. $$ - 9$$
D. $$ - 3$$
Releted Question 4

If the line $$x-1=0$$   is the directrix of the parabola $${y^2} - kx + 8 = 0,$$    then one of the values of $$k$$ is-

A. $$\frac{1}{8}$$
B. $$8$$
C. $$4$$
D. $$\frac{1}{4}$$

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Parabola


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