The cardinality of the set $$P\left\{ {P\left[ {P\left( \phi \right)} \right]} \right\}$$ is :
A.
$$0$$
B.
$$1$$
C.
$$2$$
D.
$$4$$
Answer :
$$4$$
Solution :
$$P\left( \phi \right)$$ is the power set of the set $$\phi .$$
$$\therefore $$ Cardinality $$ = P\left\{ {P\left[ {P\left( \phi \right)} \right]} \right\} = 4$$
Releted MCQ Question on Calculus >> Sets and Relations
Releted Question 1
If $$X$$ and $$Y$$ are two sets, then $$X \cap {\left( {X \cup Y} \right)^c}$$ equals.