The area bounded by the curve $$y = {\sin ^{ - 1}}x$$ and the line $$x = 0,\,\left| y \right| = \frac{\pi }{2}$$ is :
A.
$$1$$
B.
$$2$$
C.
$$\pi $$
D.
$$2\pi $$
Answer :
$$2$$
Solution :
The required area is shown by shaded portion in the figure.
The required area is $$A = \int\limits_{ - \frac{\pi }{2}}^{\frac{\pi }{2}} {\left| {\sin \,y} \right|dy = 2\int\limits_0^{\frac{\pi }{2}} {\sin \,y\,dy} = 2} $$
Releted MCQ Question on Calculus >> Application of Integration
Releted Question 1
The area bounded by the curves $$y = f\left( x \right),$$ the $$x$$-axis and the ordinates $$x = 1$$ and $$x = b$$ is $$\left( {b - 1} \right)\sin \left( {3b + 4} \right).$$ Then $$f\left( x \right)$$ is-