Sum of coefficients in the exansion of $${\left( {x + 2y + 3z} \right)^{10}}\,$$ is
A.
$${2^{10}}$$
B.
$${3^{10}}$$
C.
$$1$$
D.
$${6^{10}}$$
Answer :
$${6^{10}}$$
Solution :
Put $$x = y = z = 1,$$ the sum of coefficient $$ = {\left( {1 + 2 + 3} \right)^{10}} = {6^{10}}.$$
Releted MCQ Question on Algebra >> Binomial Theorem
Releted Question 1
Given positive integers $$r > 1, n > 2$$ and that the co - efficient of $${\left( {3r} \right)^{th}}\,{\text{and }}{\left( {r + 2} \right)^{th}}$$ terms in the binomial expansion of $${\left( {1 + x} \right)^{2n}}$$ are equal. Then
If in the expansion of $${\left( {1 + x} \right)^m}{\left( {1 - x} \right)^n},$$ the co-efficients of $$x$$ and $${x^2}$$ are $$3$$ and $$- 6\,$$ respectively, then $$m$$ is