Let $$P = \left\{ {\left( {x,\,y} \right):\left| {{x^2} + {y^2}} \right| = 1,\,x,\,y\, \in \,R\,} \right\}.$$ Then $$P$$ is :
A.
Reflexive
B.
Symmetric
C.
Transitive
D.
Anti-symmetric
Answer :
Symmetric
Solution :
Obviously, the relation is not reflexive and transitive but it is symmetric, because $${x^2} + {y^2} = 1\,\, \Rightarrow {y^2} + {x^2} = 1$$
Releted MCQ Question on Calculus >> Sets and Relations
Releted Question 1
If $$X$$ and $$Y$$ are two sets, then $$X \cap {\left( {X \cup Y} \right)^c}$$ equals.