Question

If the latus rectum of an ellipse is equal to one half its minor axis, what is the eccentricity of the ellipse ?

A. $$\frac{1}{2}$$
B. $$\frac{{\sqrt 3 }}{2}$$  
C. $$\frac{3}{4}$$
D. $$\frac{{\sqrt {15} }}{4}$$
Answer :   $$\frac{{\sqrt 3 }}{2}$$
Solution :
Length of latus rectum of an ellipse is $$\frac{{2{b^2}}}{a}$$  where $$b$$ is semi minor axis and $$a$$ is semimajor axis. As given,
$$\frac{{2{b^2}}}{a} = b\, \Rightarrow 2b = a\, \Rightarrow \frac{b}{a} = \frac{1}{2}$$
We know that eccentricity $$e = \sqrt {1 - \frac{{{b^2}}}{{{a^2}}}} = \sqrt {1 - \frac{1}{4}} = \frac{{\sqrt 3 }}{2}$$

Releted MCQ Question on
Geometry >> Ellipse

Releted Question 1

Let $$E$$ be the ellipse $$\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1$$   and $$C$$ be the circle $${x^2} + {y^2} = 9.$$   Let $$P$$ and $$Q$$ be the points $$\left( {1,\,2} \right)$$  and $$\left( {2,\,1} \right)$$  respectively. Then-

A. $$Q$$ lies inside $$C$$ but outside $$E$$
B. $$Q$$ lies outside both $$C$$ and $$E$$
C. $$P$$ lies inside both $$C$$ and $$E$$
D. $$P$$ lies inside $$C$$ but outside $$E$$
Releted Question 2

The radius of the circle passing through the foci of the ellipse $$\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1,$$   and having its centre at $$\left( {0,\,3} \right)$$  is-

A. $$4$$
B. $$3$$
C. $$\sqrt {\frac{1}{2}} $$
D. $$\frac{7}{2}$$
Releted Question 3

The area of the quadrilateral formed by the tangents at the end points of latus rectum to the ellipse $$\frac{{{x^2}}}{9} + \frac{{{y^2}}}{5} = 1,$$    is-

A. $$\frac{{27}}{4}\,\,{\text{sq}}{\text{.}}\,{\text{units}}$$
B. $$9\,\,{\text{sq}}{\text{.}}\,{\text{units}}$$
C. $$\frac{{27}}{2}\,\,{\text{sq}}{\text{.}}\,{\text{units}}$$
D. $$27\,\,{\text{sq}}{\text{.}}\,{\text{units}}$$
Releted Question 4

If tangents are drawn to the ellipse $${x^2} + 2{y^2} = 2,$$   then the locus of the mid-point of the intercept made by the tangents between the coordinate axes is-

A. $$\frac{1}{{2{x^2}}} + \frac{1}{{4{y^2}}} = 1$$
B. $$\frac{1}{{4{x^2}}} + \frac{1}{{2{y^2}}} = 1$$
C. $$\frac{{{x^2}}}{2} + \frac{{{y^2}}}{4} = 1$$
D. $$\frac{{{x^2}}}{4} + \frac{{{y^2}}}{2} = 1$$

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Ellipse


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