Releted MCQ Question on 
Algebra >> Mathematical Reasoning  
    
 Releted Question 1
  
    Let $$p$$ be the statement “$$x$$ is an irrational number”, $$q$$ be the statement “$$y$$ is a transcendental number”, and $$r$$ be the statement “$$x$$ is a rational number if $$f y$$  is a transcendental number”.
Statement - 1 : $$r$$ is equivalent to either $$q$$ or $$p$$
Statement - 2 : $$r$$ is equivalent to $$ \sim \left( {p \leftrightarrow  \sim q} \right).$$  
   A.
    Statement - 1 is false, Statement - 2 is true
  
   B.
    Statement - 1 is true, Statement - 2 is true ; Statement - 2 is
a correct explanation for Statement - 1
  
   C.
    Statement - 1 is true, Statement - 2 is true ; Statement - 2
is not a correct explanation for Statement - 1
  
   D.
    none of these
  
    
 
    
 Releted Question 2
  
    The statement $$p \to \left( {q \to p} \right)$$   is equivalent to  
   A.
    $$p \to \left( {p \to q} \right)$$
  
   B.
    $$p \to \left( {p \vee q} \right)$$
  
   C.
    $$p \to \left( {p \wedge q} \right)$$
  
   D.
    $$p \to \left( {p \leftrightarrow q} \right)$$
  
    
 
    
 Releted Question 3
  
    Statement - 1 : $$ \sim \left( {p \leftrightarrow  \sim q} \right)$$   is equivalent to $${p \leftrightarrow q}.$$
Statement - 2 : $$ \sim \left( {p \leftrightarrow  \sim q} \right)$$   is a tautology                                                                                                          
   A.
    Statement - 1 is true, Statement - 2 is true;
Statement - 2 is not a correct explanation for Statement - 1.
  
   B.
    Statement - 1 is true, Statement - 2 is false.
  
   C.
    Statement - 1 is false, Statement - 2 is true.
  
   D.
    Statement - 1 is true, Statement - 2 is true,
Statement - 2 is a correct explanation for statement - 1
  
    
 
    
 Releted Question 4
  
    Consider the following statements
$$P$$ : Suman is brilliant
$$Q$$ : Suman is rich
$$R$$ : Suman is honest
The negation of the statement “Suman is brilliant and dishonest if and only if Suman is rich” can be expressed as  
   A.
    $$ \sim \left( {Q \leftrightarrow \left( {P \wedge  \sim R} \right)} \right)$$
  
   B.
    $$ \sim Q \leftrightarrow  \sim P \wedge R$$
  
   C.
    $$ \sim \left( {P \wedge  \sim R} \right) \leftrightarrow Q$$
  
   D.
    $$ \sim P \wedge \left( {Q \leftrightarrow  \sim R} \right)$$