if f x 20c cos x and sin x and 0 sin x and cos x and 0 0

If \[f\left( x \right) = \left[ {\begin{array}{*{20}{c}} {\cos x}&{ - \sin x}&0 \\ {\sin x}&{\cos x}&0 \\ 0&0&1 \end{array}} \right]\] then $$f\left( {x + y} \right)$$ is equal to

A. $$f\left( x \right) + f\left( y \right)$$

B. $$f\left( x \right) - f\left( y \right)$$

C. $$f\left( x \right) \cdot f\left( y \right)$$

D. None of these

Answer : $$f\left( x \right) \cdot f\left( y \right)$$

Solution :
\[f\left( {x + y} \right) = \left[ {\begin{array}{*{20}{c}} {\cos \left( {x + y} \right)}&{ - \sin \left( {x + y} \right)}&0 \\ {\sin \left( {x + y} \right)}&{\cos \left( {x + y} \right)}&0 \\ 0&0&1 \end{array}} \right]\]
\[f\left( {x + y} \right) = \left[ {\begin{array}{*{20}{c}} {\cos x}&{ - \sin x}&0 \\ {\sin x}&{\cos x}&0 \\ 0&0&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {\cos y}&{ - \sin y}&0 \\ {\sin y}&{\cos y}&0 \\ 0&0&1 \end{array}} \right] = f\left( x \right) \cdot f\left( y \right).\]

Releted MCQ Question on
Algebra >> Matrices and Determinants

Releted Question 1

Consider the set $$A$$ of all determinants of order 3 with entries 0 or 1 only. Let $$B$$ be the subset of $$A$$ consisting of all determinants with value 1. Let $$C$$ be the subset of $$A$$ consisting of all determinants with value $$- 1.$$ Then

A. $$C$$ is empty

B. $$B$$ has as many elements as $$C$$

C. $$A = B \cup C$$

D. $$B$$ has twice as many elements as elements as $$C$$

View Answer

Releted Question 2

If $$\omega \left( { \ne 1} \right)$$ is a cube root of unity, then
\[\left| {\begin{array}{*{20}{c}} 1&{1 + i + {\omega ^2}}&{{\omega ^2}}\\ {1 - i}&{ - 1}&{{\omega ^2} - 1}\\ { - i}&{ - i + \omega - 1}&{ - 1} \end{array}} \right|=\]

A. 0

B. 1

C. $$i$$

D. $$\omega $$

View Answer

Releted Question 3

Let $$a, b, c$$ be the real numbers. Then following system of equations in $$x, y$$ and $$z$$
$$\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} - \frac{{{z^2}}}{{{c^2}}} = 1,$$ $$\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} + \frac{{{z^2}}}{{{c^2}}} = 1,$$ $$ - \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} + \frac{{{z^2}}}{{{c^2}}} = 1$$ has

A. no solution

B. unique solution

C. infinitely many solutions

D. finitely many solutions

View Answer

Releted Question 4

If $$A$$ and $$B$$ are square matrices of equal degree, then which one is correct among the followings?

A. $$A + B = B + A$$

B. $$A + B = A - B$$

C. $$A - B = B - A$$

D. $$AB=BA$$

View Answer

If \[f\left( x \right) = \left[ {\begin{array}{*{20}{c}} {\cos x}&{ - \sin x}&0 \\ {\sin x}&{\cos x}&0 \\ 0&0&1 \end{array}} \right]\] then $$f\left( {x + y} \right)$$ is equal to

Releted MCQ Question on
Algebra >> Matrices and Determinants

Consider the set $$A$$ of all determinants of order 3 with entries 0 or 1 only. Let $$B$$ be the subset of $$A$$ consisting of all determinants with value 1. Let $$C$$ be the subset of $$A$$ consisting of all determinants with value $$- 1.$$ Then

If $$\omega \left( { \ne 1} \right)$$ is a cube root of unity, then
\[\left| {\begin{array}{*{20}{c}} 1&{1 + i + {\omega ^2}}&{{\omega ^2}}\\ {1 - i}&{ - 1}&{{\omega ^2} - 1}\\ { - i}&{ - i + \omega - 1}&{ - 1} \end{array}} \right|=\]

If $$A$$ and $$B$$ are square matrices of equal degree, then which one is correct among the followings?

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Matrices and Determinants

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If \[f\left( x \right) = \left[ {\begin{array}{*{20}{c}} {\cos x}&{ - \sin x}&0 \\ {\sin x}&{\cos x}&0 \\ 0&0&1 \end{array}} \right]\] then $$f\left( {x + y} \right)$$ is equal to

Releted MCQ Question on Algebra >> Matrices and Determinants

Consider the set $$A$$ of all determinants of order 3 with entries 0 or 1 only. Let $$B$$ be the subset of $$A$$ consisting of all determinants with value 1. Let $$C$$ be the subset of $$A$$ consisting of all determinants with value $$- 1.$$ Then

If $$\omega \left( { \ne 1} \right)$$ is a cube root of unity, then \[\left| {\begin{array}{*{20}{c}} 1&{1 + i + {\omega ^2}}&{{\omega ^2}}\\ {1 - i}&{ - 1}&{{\omega ^2} - 1}\\ { - i}&{ - i + \omega - 1}&{ - 1} \end{array}} \right|=\]

If $$A$$ and $$B$$ are square matrices of equal degree, then which one is correct among the followings?

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Practice More MCQ Question on Maths Section

Releted MCQ Question on
Algebra >> Matrices and Determinants

If $$\omega \left( { \ne 1} \right)$$ is a cube root of unity, then
\[\left| {\begin{array}{*{20}{c}} 1&{1 + i + {\omega ^2}}&{{\omega ^2}}\\ {1 - i}&{ - 1}&{{\omega ^2} - 1}\\ { - i}&{ - i + \omega - 1}&{ - 1} \end{array}} \right|=\]

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Matrices and Determinants