Question
A man whose eye level is 1.5 metres above the ground observes the angle of elevation of the tower to be $${{{60}^ \circ }}.$$ If the distance of the man from the tower be 10 metres, the height of the tower is
A.
$$\left( {1.5 + 10\sqrt 3 } \right)m$$
B.
$${10\sqrt 3 } \, m$$
C.
$$\left( {1.5 + \frac{{10}}{{\sqrt 3 }}} \right)m$$
D.
None of these
Answer :
$$\left( {1.5 + 10\sqrt 3 } \right)m$$
Solution :
$$\eqalign{ & H = \left( {10\tan {{60}^ \circ } + 1.5} \right) \cr & = \left( {10\sqrt 3 + 1.5} \right)m \cr} $$
$$\eqalign{ & H = \left( {10\tan {{60}^ \circ } + 1.5} \right) \cr & = \left( {10\sqrt 3 + 1.5} \right)m \cr} $$