Baeyer's reagent $$\left( {alk.\,KMn{O_4}} \right)$$ which is pink in colour is decolourised due to presence of unsaturation.
44.
The treatment of $$C{H_3}MgX$$ with $$C{H_3}C \equiv C - H$$ produces
A
$$C{H_3} - CH = C{H_2}$$
B
$$C{H_3}C \equiv C - C{H_3}$$
C
\[C{{H}_{3}}-\overset{\begin{smallmatrix}
H \\
|
\end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix}
H \\
|
\end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]
Writing the reaction we get
$$C{H_3}MgX + C{H_3} - C \equiv C - H \to $$ $$C{H_3} - C \equiv CMgX + C{H_4}\left( g \right)$$
So we find that $$C{H_4}$$ is produced in this reaction.
45.
Reaction of one molecule of $$HBr$$ with one molecule of 1, 3 - butadiene at $${40^ \circ }C$$ gives predominantly
A
1 - bromo - 2 - butene under kinetically controlled
conditions
B
3 - bromobutene under thermodynamically controlled predominantly
conditions
C
1 - bromo - 2 - butene under thermodynamically controlled conditions
D
3 - bromobutene under kinetically controlled conditions
Due to the maximum percentage of $$s$$ - character (50%), the $$sp$$ hybridised orbitals of carbon atoms in ethyne molecules have highest electro negativity, thus in ethyne, hydrogen atoms can be liberated as protons most easily.
48.
When acetylene is passed through $$dil \cdot {H_2}S{O_4}$$ in presence of $$HgS{O_4},$$ the compound formed is
When two groups attached to a double bonded carbon atoms are same, the compound does not exhibit geometrical isomerism. Only 2-butene exhibits $$cis{\text{ - }}trans{\text{ }}$$ isomerism.
50.
The major product of the following reaction sequence is : \[\xrightarrow[2.\,{{H}_{2}}{{O}_{2}},\,H{{O}^{-}}]{1.\,{{B}_{2}}{{H}_{6}}}?\]