Ethyne (acetylene) have shortest $$C-C$$ bond length because it have $$C \equiv C$$ i.e. triple bond. The bond length follows the following order
$$C \equiv C < C = C < C - C$$
122.
The reaction of propene with $$HOCl\left( {C{l_2} + {H_2}O} \right)$$ proceeds through the intermediate :
Kekule in 1865 proposed a ring structure for benzene in which the position of the three double bonds are not fixed. He suggested that the double bond keeps on changing their position and this is called resonance. According to Kekule, benzene is a resonance hybrid of two structures (a) and (b) and the hybrid structure may be represented as (c). The (a) and (b) are called resonating structures and are represented by putting $$\left( \leftrightarrow \right)$$ double headed arrow between them.
125.
Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is diazotised and then heated wth cuprous bromide. The reaction mixture so formed contans
A
mixture of $$o - $$ and $$p - $$ bromotoluenes
B
mixture of $$o - $$ and $$p - $$ dibromobenzenes
C
mixture of $$o - $$ and $$p - $$ bromoanilines
D
mixture of $$o - $$ and $$m - $$ bromotoluenes
Answer :
mixture of $$o - $$ and $$p - $$ bromotoluenes
NOTE : Toluene contains $$ - C{H_3}$$ group which
is $$o - ,p - $$ directing group so on nitration of toluene the $$ - N{O_2}$$ group will occupy $$o - ,p - $$ poditions.
on reduction with $$Sn/HCl$$ they will form corresponding anilines in which $$ - N{O_2}$$ group changes to $$ - N{H_2}.$$ The
mixture now contains
anilines when diazotized and then treated with $$CuBr$$ forms
$$o - ,p - $$ bromotoluenes.
No explanation is given for this question. Let's discuss the answer together.
128.
One mole of 1, 2-dibromopropane on treatment with $$X$$ moles of $$NaN{H_2}$$ followed by treatment with ethyl bromide gave 2-pentyne. The value of $$X$$ is
$$NHCOC{H_3}$$ is more activating than isopropyl group.
130.
Similar to alkenes and alkynes benzene also undergoes ozonolysis. In the sequence of the given reaction identify $$X$$ and $$Y.$$ \[+\,{{O}_{3}}\to X\xrightarrow{\frac{Zn}{{{H}_{2}}O}}Y\]