Non superimposable mirror images are called optical isomers and may be described as “chiral’. They are also called enantiomers and rotate plane polarised light in opposite directions.
302.
The IUPAC name of the coordination compound $${K_3}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$$ is
304.
Which one of the following is an inner orbital complex as well as diamagnetic in behaviour ?
$$\left( {{\text{At}}{\text{. no}}{\text{. of}}\,\,Zn = 30,Cr = 24,Co = 27,Ni = 28} \right)$$
A
$${\left[ {Zn{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }}$$
B
$${\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
C
$${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
D
$${\left[ {Ni{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }}$$
In $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }},$$ oxidation state of $$Co = + 3$$ and its coordination number is six.
$$\eqalign{
& _{27}Co = 1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^7},4{s^2} \cr
& C{o^{3 + }} = 1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^6} \cr} $$
$${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$ is an inner orbital complex as well as diamagnetic in behaviour ( due to absence of unpaired electrons ).
$${\left[ {Zn{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }} \to s{p^3}{d^2}$$ hybridisation ( outer orbital complex and diamagnetic in nature ).
$${\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }} \to {d^2}s{p^3}$$ hybridisation ( inner orbital complex and paramagnetic in nature ).
305.
The shape of $${\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]^{2 + }}$$ is
Shape of $${\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]^{2 + }}$$ is square planar.
306.
Two complexes $$\left[ {Cr\left( {{H_2}{O_6}} \right)} \right]C{l_3}\left( A \right)\,{\text{and}}\,\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]C{l_3}\left( B \right)$$ are violet and yellow coloured, respectively. The incorrect statement regarding them is:
A values of $$\left( A \right)\,{\text{and}}\,\left( B \right)$$ are calculated from the energies of biolet and yellow light, respectively.
B
both are paramagnetic with three unpaired electrons.
C
both absorb energies corresponding to their complementary colors.
D value for $$\left( A \right)$$ is less than that $$\left( B \right).$$
Answer : values of $$\left( A \right)\,{\text{and}}\,\left( B \right)$$ are calculated from the energies of biolet and yellow light, respectively.
$$E.C.\,{\text{of}}\,C{r^{3 + }}\left( {3{d^3}} \right):$$
For complex A $${\left[ {Cr{{\left( {{H_2}O} \right)}_2}} \right]^{3 + }}:$$
For complex B $${\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}:$$
Here, both the complexes $$\left( A \right)\,{\text{and}}\,\left( B \right)$$ are paramagnetic with $$3$$ unpaired electrons each. Also $$H2O$$ is a weak field ligand which causes lesser splitting than NH3 which is comparatively stronger field ligand. Hence, the $$\left( {D0} \right)$$ value of $$\left( A \right)\,{\text{and}}\,\left( B \right)$$ are calculated from the wavelengths of light absorbed and not from the wavelengths of light emitted.
307.
Which of the following is correct?
A
Valence bond theory explains the colour of the coordination compounds.
B
$${\left[ {NiC{l_4}} \right]^{2 - }}$$ is diamagnetic in nature.
C
Ambident ligands can show linkage isomerism.
D
A bidentate ligand can have four coordination
sites.
Answer :
Ambident ligands can show linkage isomerism.
Due to some backbonding by sidewise overlapping of between $$d{\text{ - orbitals}}$$ of metal and $$p{\text{ - orbitals}}$$ of carbon, the $$Fe - C$$ bond in $$Fe{\left( {CO} \right)_5}$$ has both $$\sigma $$ and $$\pi $$ character.
309.
The correct name for the complex ion $${\left[ {CoCl\left( {ONO} \right){{\left( {en} \right)}_2}} \right]^ + }$$ is :
A
chlorobis ( ethylenediamine ) nitrito - $$O$$ - cobaltate (III) ion
B
chlorodiethyldiaminenitrito - $$O$$ - cobalt (III) ion
C
chloronitrito - $$O$$ - diethyldiamine cobaltate (III) ion
D
chlorobis ( ethylenediamine ) nitrito - $$O$$ - cobalt (III) ion
As number of stable rings increases stability of complex compound also increases due to chelation effect.
Number of rings in $${\left[ {Ni{{\left( {en} \right)}_2}} \right]^{2 + }} = 2$$
Number of rings in $$\left[ {Ni{{\left( {dmg} \right)}_2}} \right] = 4$$