71.
The magnetic flux $$\phi $$ linked with a conducting coil depends on time as $$\phi = 4{t^n} + 6,$$ where $$n$$ is a positive constant. The induced emf in the coil is $$e.$$ Then which is wrong?
A
If $$0 < n < 1,\,e \ne 0$$ and $$\left| e \right|$$ decreases with time
B
If $$n = 1,$$ $$e$$ is constant
C
If $$n > 1,\left| e \right|$$ increases with time
D
If $$n > 1,\left| e \right|$$ decreases with time
Answer :
If $$n > 1,\left| e \right|$$ decreases with time
72.
In a uniform magnetic field of induction $$B$$ a wire in the form of a semicircle of radius $$r$$ rotates about the diameter of the circle with an angular frequency $$\omega .$$ The axis of rotation is perpendicular to the field. If the total resistance of the circuit is $$R,$$ the mean power generated per period of rotation is
A
$$\frac{{{{\left( {B\pi r\omega } \right)}^2}}}{{2R}}$$
B
$$\frac{{{{\left( {B\pi {r^2}\omega } \right)}^2}}}{{8R}}$$
C
$$\frac{{B\pi {r^2}\omega }}{{2R}}$$
D
$$\frac{{{{\left( {B\pi r{\omega ^2}} \right)}^2}}}{{8R}}$$
73.
A superconducting loop of radius $$R$$ has self inductance $$L.$$ A uniform and constant magnetic field $$B$$ is applied perpendicular to the plane of the loop. Initially current in this loop is zero. The loop is rotated by $${180^ \circ }.$$ The current in the loop after rotation is equal to
Flux can’t change in a superconducting loop.
$$\Delta \phi = 2\pi {R^2}.B$$
Initially current was zero, so self flux was zero.
$$\therefore $$ Finally $$Li = 2\pi {R^2} \times B$$
$$i = \frac{{2\pi {R^2} \times B}}{L}$$
74.
A resistance less ring has 2 bulbs $$A$$ and $$B$$ rated at $$2V,10\,W$$ and $$2V,20\,W$$ respectively. The ring encloses an ideal solenoid whose magnetic field is as shown. The radius of solenoid is $$1\,m$$ and the number of $$\frac{{{\text{turns}}}}{{{\text{length}}}} = 1000/m.$$ The current changes at rate of $$9\,A/\sec.$$ Find the value of $$P$$ if power dissipated in bulb $$B$$ is $$1.8\,P \times {10^{ - 4}}\,watt.$$
75.
There are three wire $$MO,NO$$ and $$PQ,$$ wires $$MO$$ and $$NO$$ are fixed and perpendicular to each other. Wire $$PQ$$ moves with a constant velocity $$v$$ as shown in the figure and resistance per unit length of each wire is $$\lambda $$ and magnetic field exists perpendicular and inside the paper then Which of the following is wrong?
A
current in loop is anticlockwise
B
magnitude of current in the loop is $$\frac{{Bv}}{{\lambda \left( {\sqrt 2 + 1} \right)}}$$
C
current in the loop is independent of time.
D
magnitude of current decreases as time increases.
Answer :
magnitude of current decreases as time increases.
76.
Magnetic flux linked with a stationary loop of resistance $$R$$ varies with respect to time during the time period $$T$$ as follows:
$$\phi = at\left( {T - t} \right)$$
The amount of heat generated in the loop during that time (inductance of the coil is negligible) is
Given that $$\phi = at\left( {T - t} \right)$$
Induced emf, $$E = \frac{{d\phi }}{{dt}} = \frac{d}{{dt}}\left[ {at\left( {T - t} \right)} \right]$$
$$ = at\left( {0 - 1} \right) + a\left( {T - t} \right) = a\left( {T - 2t} \right)$$
So, induced emf is also a function of time.
$$\therefore $$ Heat generated in time $$T$$ is
$$H\int\limits_0^T {\frac{{{E^2}}}{R}} dt = \frac{{{a^2}}}{R}\int\limits_0^T {{{\left( {T - 2t} \right)}^2}} dt = \frac{{{a^2}{T^3}}}{{3R}}$$
77.
In the figure the flux through the loop perpendicular to the plane of the coil and directed into the paper is varying according to the relation $$\phi = 6{t^2} + 7t + 1$$ where $$\phi $$ is in milliweber and $$t$$ is in second. The magnitude of the emf induced in the loop at $$t = 2\,s$$ and the direction of induce current through $$R$$ are
$$\eqalign{
& \phi = 6{t^2} + 7t + 1 \cr
& \Rightarrow \frac{{d\phi }}{{dt}} = 12t + 7 \cr} $$
At time, $$t = 2\,\sec.$$
$$\frac{{d\phi }}{{dt}} = 24 + 7 = 31\,mv$$
Direction of current is from left to right according to Flemings right hand rule.
78.
A conducting square frame of side $$'a'$$ and a long straight wire carrying current $$I$$ are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity $$'V'.$$ The emf induced in the frame will be proportional to
A
$$\frac{1}{{{{\left( {2x - a} \right)}^2}}}$$
B
$$\frac{1}{{{{\left( {2x + a} \right)}^2}}}$$
C
$$\frac{1}{{\left( {2x - a} \right)\left( {2x + a} \right)}}$$
Emf induced in side 1 of frame $${e_1} = {B_1}V\ell $$
$${B_1} = \frac{{{\mu _0}I}}{{2\pi \left( {x - \frac{a}{2}} \right)}}$$
Emf induced in side 2 of frame $${e_2} = {B_2}V\ell $$
$${B_2} = \frac{{{\mu _0}I}}{{2\pi \left( {x + \frac{a}{2}} \right)}}$$
Emf induced in square frame
$$\eqalign{
& e = {B_1}V\ell - {B_2}V\ell \cr
& = \frac{{{\mu _0}I}}{{2\pi \left( {x - \frac{a}{2}} \right)}}\ell v - \frac{{{\mu _0}I}}{{2\pi \left( {x + \frac{a}{2}} \right)}}\ell v \cr
& {\text{or,}}\,\,e \propto \frac{1}{{\left( {2x - a} \right)\left( {2x + a} \right)}} \cr} $$
79.
A coil of resistance $$400\,\Omega $$ is placed in a magnetic field. If the magnetic flux $$\phi \left( {Wb} \right)$$ linked with the coil varies with time $$t$$ (second) as $$\phi = 50\,{t^2} + 4.$$
The current in the coil at $$t = 2\,s$$ is
Induced emf in a coil is given by
$$E = \left| { - \frac{{d\phi }}{{dt}}} \right|$$
Given, $$\phi = 50\,{t^2} + 4\,$$
and resistance, $$R = 400\,\Omega $$
So, $$E = {\left| { - \frac{{d\phi }}{{dt}}} \right|_{t = 2}} = {\left| {100\,t} \right|_{t = 2}} = 200\,V$$
So, current in the coil will be
$$I = \frac{E}{R} = \frac{{200}}{{400}} = \frac{1}{2} = 0.5\,A$$
80.
Shown in the figure is a circular loop of radius $$r$$ and resistance $$R.$$ A variable magnetic field of induction $$B = {B_0}{e^{ - t}}$$ is established inside the coil. If the key $$\left( K \right)$$ is closed, the electrical power developed right after closing the switch is equal to