This reaction is an example of “Perkin reaction”. The compound X should be $${\left( {C{H_3}CO} \right)_2}O.$$
In this step the carbanion is obtained by removal of an $$\alpha - H$$ atom from a molecule of an acid anhydride, the anion of the corresponding acid acting as a necessary base.
52.
A compound $$(X)$$ with a molecular formula $${C_5}{H_{10}}O$$ gives a positive 2, 4-$$DNP$$ test but a negative Tollens' test. On oxidation it gives a carboxylic acid $$(Y)$$ with a molecular formula $${C_3}{H_6}{O_2}.$$ Potassium salt of $$(Y)$$ undergoes Kolbe's reaction and gives a hydrocarbon $$(Z).$$ $$(X), (Y)$$ and $$(Z)$$ respectively are
2, 2-Dimethylpropanoic acid will not undergo $$HVZ$$ reaction due to absence of $$\alpha {\text{ - }}H$$ atom.
55.
In the following sequence of reactions, what is $$D?$$ \[\xrightarrow{\left[ O \right]}A\]
\[A\xrightarrow{SOC{{l}_{2}}}B\xrightarrow{Na{{N}_{3}}}C\xrightarrow{\text{heat}}D\]
\[{{C}_{6}}{{H}_{5}}C{{H}_{3}}\xrightarrow{\left[ O \right]}\underset{\left[ A \right]}{\mathop{{{C}_{6}}{{H}_{5}}COOH}}\,\] \[\xrightarrow{SOC{{l}_{2}}}\underset{\left[ B \right]}{\mathop{{{C}_{6}}{{H}_{5}}COCl}}\,\xrightarrow{Na{{N}_{3}}}\] \[\underset{\left[ C \right]}{\mathop{{{C}_{6}}{{H}_{5}}CO{{N}_{3}}}}\,\xrightarrow{\text{heat}}\] \[\underset{\text{Phenyl isocyanate,}\left[ D \right]}{\mathop{\to {{C}_{6}}{{H}_{5}}NCO}}\,\]
56.
The major product $$H$$ of the given reaction sequence is
\[C{{H}_{3}}-C{{H}_{2}}-CO-C{{H}_{3}}\xrightarrow{\overset{\Theta }{\mathop{C}}\,N}\] \[G\xrightarrow[{{\text{Heat}}}]{{95\% \,\,{H_2}S{O_4}}}H\]
58.
Which of the following represent the correct decreasing order of acidic strength of
following?
(i) Methanoic acid
(ii) Ethanoic acid
(ii) Propanoic acid
(iv) Butanoic acid
Only acetic acid is more acidic than carbonic acid ( conjugate acid of \[NaHC{{O}_{3}}\] ) hence it dissolves in \[NaHC{{O}_{3}},\]
\[\underset{\text{stronger acid}}{\mathop{C{{H}_{3}}COOH}}\,+NaHC{{O}_{3}}\to \] \[C{{H}_{3}}CO{{O}^{-}}N{{a}^{+}}+\underset{\text{weaker acid}}{\mathop{{{H}_{2}}C{{O}_{3}}}}\,\left( {{H}_{2}}O+C{{O}_{2}} \right)\]
while phenol and $$n$$ - hexanol are less acidic than carbonic acid and hence do not dissolve in \[NaHC{{O}_{3}}.\]