341. Acidified $${K_2}C{r_2}{O_7}$$   solution turns green when $$N{a_2}S{O_3}$$  is added to it. This is due to the formation of

A $$CrO_4^{2 - }$$
B $$C{r_2}{\left( {S{O_3}} \right)_3}$$
C $$CrS{O_4}$$
D $$C{r_2}{\left( {S{O_4}} \right)_3}$$
Answer :   $$C{r_2}{\left( {S{O_4}} \right)_3}$$
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