251.
When $$KMn{O_4}$$ acts as an oxidising agent and ultimately forms $${\left[ {Mn{O_4}} \right]^{ - 2}},Mn{O_2},M{n_2}{O_3},M{n^{ + 2}}$$ then the number of electrons transfered in each case respectively is
A
$$4,3,1,5$$
B
$$1,5,3,7$$
C
$$1,3,4,5$$
D
$$3,5,7,1.$$
Answer :
$$1,3,4,5$$
252.
How many unpaired electrons are present in $$N{i^{2 + }}$$ ?
A
$$0$$
B
$$2$$
C
$$4$$
D
$$8$$
Answer :
$$2$$
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It has $$2$$ unpaired electrons.
$$3d$$ orbital of $$N{i^{2 + }}$$ ion.At No.of $$Ni = 28.$$
253.
The melting points of $$Cu,Ag$$ and $$Au$$ follow the order
A
$$Cu > Ag > Au$$
B
$$Cu > Au > Ag$$
C
$$Au > Ag > Cu$$
D
$$Ag > Au > Cu$$
Answer :
$$Cu > Au > Ag$$
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254.
Which one of the following nitrates will leave behind a metal on strong heating?
A
Copper nitrate
B
Manganese nitrate
C
Silver nitrate
D
Ferric nitrate
Answer :
Silver nitrate
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$$AgN{O_3}$$ on heating till red hot decomposes as follows:
$$AgN{O_3} \to Ag + N{O_2} + \frac{1}{2}{O_2}$$
255.
Identify the incorrect statement among the following.
A
$$4f$$ and $$5f$$ orbitals are equally shielded.
B
$$d$$ - Block elements show irregular and erratic chemical properties among themselves.
C
$$La$$ and $$Lu$$ have partially filled $$d$$ - orbitals and no other partially filled orbitals.
D
The chemistry of various lanthanoids is very similar.
Answer :
$$4f$$ and $$5f$$ orbitals are equally shielded.
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The decrease in the force of attraction exerted by the nucleus on the valence electrons due to presence of electrons in the inner shells is called shielding effect. A $$4f$$ orbital is nearer to the nucleus than $$5f$$ orbital. Hence shielding of $$4f$$ is more than $$5f.$$
256.
The trend of basicity of lanthanoid hydroxides
A
increases across the lanthanoid series
B
decreases across the lanthanoid series
C
first increases and then decreases
D
first decreases and then increases
Answer :
decreases across the lanthanoid series
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Basicity of lanthanoid hydroxides decreases across the series due to decrease in ionic radii across the series.
257.
Which one of the following ions is the most stable in aqueous solution?
$$\left( {{\text{At}}{\text{. no}}{\text{.}}\,Ti = 22,V = 23,} \right.$$ $$\left. {Cr = 24,Mn = 25} \right)$$
A
$$C{r^{3 + }}$$
B
$${V^{3 + }}$$
C
$$T{i^{3 + }}$$
D
$$M{n^{3 + }}$$
Answer :
$$M{n^{3 + }}$$
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Stability of transition metal ions is directly proportional to the unpaired electrons. The exactly half-filled and completely filled $$d$$-orbitals are extra stable.
$$C{r^{3 + }}\left( {21} \right) = 3{d^3},4{s^0}$$ ( 3 unpaired electrons )
$${V^{3 + }}\left( {20} \right) = 3{d^2},4{s^0}$$ ( 2 unpaired electrons )
$$T{i^{3 + }}\left( {19} \right) = 3{d^1},4{s^0}$$ ( 1 unpaired electron )
$$M{n^{3 + }}\left( {22} \right) = 3{d^4},4{s^0}$$ ( 4 unpaired electrons )
So, $$M{n^{3 + }}$$ $$ion$$ is most stable in aqueous solution.
258.
In acidic medium, $$KMn{O_4}$$ oxidises $$FeS{O_4}$$ solution. Which of the following statements is correct?
A
$$10\,mL$$ of $$1\,N\,KMn{O_4}$$ solution oxidises $$10\,mL$$ of $$5\,N\,FeS{O_4}$$ solution.
B
$$10\,mL$$ of $$1\,M\,KMn{O_4}$$ solution oxidises $$10\,mL$$ of $$5\,M\,FeS{O_4}$$ solution.
C
$$10\,mL$$ of $$1\,M\,KMn{O_4}$$ solution oxidises $$10\,mL$$ of $$1\,M\,FeS{O_4}$$ solution.
D
$$10\,mL$$ of $$1\,N\,KMn{O_4}$$ solution oxidises $$10\,mL$$ of $$0.1\,M\,FeS{O_4}$$ solution.
Answer :
$$10\,mL$$ of $$1\,M\,KMn{O_4}$$ solution oxidises $$10\,mL$$ of $$5\,M\,FeS{O_4}$$ solution.
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$$2KMn{O_4} + 8{H_2}S{O_4} + 10FeS{O_4} \to $$ $${K_2}S{O_4} + 2MnS{O_4} + 5F{e_2}{\left( {S{O_4}} \right)_3}$$ $$ + 8{H_2}O$$
One mole of $$KMn{O_4}$$ oxidises five moles of $$FeS{O_4}$$ i.e., $$1\,M\,KMn{O_4}$$ can oxidise equal amount of $$5\,M\,FeS{O_4}.$$
259.
Interstitial compounds are
A
non-stoichiometric and are ionic in nature
B
non-stoichiometric and are covalent in nature
C
non-stoichiometric and are neither typically ionic nor covalent in nature
D
stoichiometric and are neither ionic nor covalent in nature
Answer :
non-stoichiometric and are neither typically ionic nor covalent in nature
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260.
Which compound does not dissolve in hot, dilute $$HN{O_3}$$ ?
A
$$HgS$$
B
$$PbS$$
C
$$CuS$$
D
$$CdS$$
Answer :
$$HgS$$
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$$HgS$$ does not dissolved in hot dil. $$HN{O_3}$$