$$Z{n^ + }\left( {{\text{at}}{\text{.}}\,{\text{no}}{\text{.}} = 30} \right) = 1{s^2},2{s^2}2{p^6},$$ $$3{s^2}3{p^6}3{d^{10}},4{s^1}$$
(no unpaired $$d$$-electrons)
$$F{e^{2 + }}\left( {{\text{at}}{\text{.}}\,{\text{no}}{\text{.}} = 26} \right) = 1{s^2},2{s^2}2{p^6},$$ $$3{s^2}3{p^6}3{d^6}$$
$${N^{3 + }}\left( {{\text{at}}{\text{.}}\,{\text{no}}{\text{.}} = 7} \right) = 1{s^2},2{s^2}2{p^0}$$
(no unpaired $$d$$-electrons)
$$C{u^ + }\left( {{\text{at}}{\text{.}}\,{\text{no}}{\text{.}} = 29} \right) = 1{s^2},2{s^2}2{p^6},$$ $$3{s^2}3{p^6}3{d^{10}}$$
(no unpaired $$d$$-electrons)
So, maximum number of unpaired electrons are present in $$F{e^{2 + }}.$$
193.
$$\eqalign{
& \left( X \right) + {K_2}C{O_3} + {\rm{Air}}\buildrel {{\rm{heat}}} \over
\longrightarrow \left( Y \right) \cr
& \left( Y \right) + C{l_2} \to \left( Z \right){\rm{Pink}} \cr} $$
Which of the following is correct ?
A
$$X = {\rm{black,}}\,Mn{O_2},\,Y = {\rm{Blue,}}\,{K_2}Cr{O_4},\,Z = KMn{O_4}$$
B
$$X = {\rm{green,}}\,C{r_2}{O_3},Y = {\rm{Yellow,}}\,{K_2}Cr{O_4},Z = {K_2}C{r_2}{O_7}$$
C
$$X = {\rm{black,}}\,Mn{O_2},Y = {\rm{green,}}\,{K_2}Mn{O_4},Z = KMn{O_4}$$
D
$$X = {\rm{black,}}\,B{i_2}{O_3},\,Y = {\rm{colourless}}\,\,KBi{O_2},Z = KBi{O_3}$$
\[\begin{align}
& \underset{\left( X \right)}{\mathop{2Mn{{O}_{2}}}}\,+2{{K}_{2}}C{{O}_{3}}+\underset{\left( \text{air} \right)}{\mathop{{{O}_{2}}}}\,\xrightarrow{\Delta }2{{K}_{2}}\,\underset{\begin{smallmatrix}
\text{green} \\
\,\,\,\left( Y \right)
\end{smallmatrix}}{\mathop{Mn{{O}_{4}}}}\,+2C{{O}_{2}}\uparrow \\
& \underset{\left( Y \right)}{\mathop{2{{K}_{2}}Mn{{O}_{4}}}}\,+C{{l}_{2}}\to \underset{\left( Z \right)\text{Pink}}{\mathop{2KMn{{O}_{4}}}}\,+2KCl \\
\end{align}\]
194.
When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is
The most stable oxidation states of lanthanides is + 3.
196.
Among the properties (a) reducing (b) oxidising (c) complexing, the set of properties shown by $$C{N^ - }\,{\text{ion}}$$ towards metal species is
In the transition elements, the $$d$$ - orbitals are successively filled. The general electronic configuration of $$d$$-block is $$\left( {n - 1} \right){d^{1 - 10}}n{s^{1 - 2}}$$
Where $$(n — 1)$$ stands for inner shell and $$d$$ - orbitals may have one to ten electrons and the $$s$$ - orbital of the outermost shell $$(n)$$ may have one or two electrons.
199.
Which of the following reactions are involved in the process of preparation of potassium dichromate?
$$\eqalign{
& \left( {\text{i}} \right)4FeC{r_2}{O_4} + 8N{a_2}C{O_3} + 7{O_2} \to \cr
& \left( {{\text{ii}}} \right)N{a_2}Cr{O_4} + {H_2}S{O_4} \to \cr
& \left( {{\text{iii}}} \right)N{a_2}C{r_2}{O_7} + 2KCl \to \cr} $$