Question
Which will form maximum boiling point azeotrope?
A.
$$HN{O_3} + {H_2}O\,\,{\text{solution}}$$
B.
$${C_2}{H_5}OH + {H_2}O\,\,{\text{solution}}$$
C.
$${C_6}{H_6} + {C_6}{H_5}C{H_3}\,\,{\text{solution}}$$
D.
$${\text{None of these}}$$
Answer :
$$HN{O_3} + {H_2}O\,\,{\text{solution}}$$
Solution :
The solutions (liquid mixture) which boils at constant temperature and can distil as such without any change in composition are called azeotropes.
Solution of $$HN{O_3}$$ and $${H_2}O$$ will form maximum boiling point azeotrope. Maximum boiling azeotropes show negative deviation from Raoult’s law.
$$\matrix{
{} & {{\rm{Composition}}\left( \% \right)} & {{\rm{Boiling Point }}} \cr
{HN{O_3}} & {68.0} & {359\,K} \cr
{{H_2}O} & {32.0} & {373\,K} \cr
} $$
Boiling point of the azeotrope of these two solutions is $$393.5\,K.$$