Question
Which one of the following reactions of xenon compounds is not feasible?
A.
$$\,3Xe{F_4} + 6{H_2}O \to 2Xe + Xe + Xe{O_3} + 12HF + 1.5{O_2}$$
B.
$$2Xe{F_2} + 2{H_2}O \to 2Xe + 4HF + {O_2}$$
C.
$$Xe{F_6} + RbF \to Rb\left[ {Xe{F_7}} \right]$$
D.
$$Xe{O_3} + 6HF \to Xe{F_6} + 3{H_2}O$$
Answer :
$$Xe{O_3} + 6HF \to Xe{F_6} + 3{H_2}O$$
Solution :
The products of the concerned reaction react each other forming back the reactants.
$$Xe{F_6} + 3{H_2}O \to Xe{O_3} + 6HF.$$