Question

Which one of the following orders of acidic strength is correct ?

A. $$RCOOH > HOH > HC \equiv CH > ROH$$
B. $$RCOOH > HC \equiv CH > HOH > ROH$$
C. $$RCOOH > ROH > HOH > HC \equiv CH$$
D. $$RCOOH > HOH > ROH > HC \equiv CH$$  
Answer :   $$RCOOH > HOH > ROH > HC \equiv CH$$
Solution :
Carboxylic acid is stronger than alcohol and water because after removal of proton, carboxylate ion is stabilised by resonance. Hence, correct order of acid strength is
$$RCOOH > HOH > ROH > HC \equiv CH$$
Which is based upon the rate of donation of proton or strength of base, thus order of basic strength is $$\mathop C\limits^ - \equiv CH > R - \mathop O\limits^ - > O{H^ - } > RCO{O^ - }$$
Carboxylic Acid mcq solution image

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

Releted Question 1

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

A. $$Cu$$
B. $$CuO$$
C. $$C{u_2}O$$
D. $$Cu + C{u_2}O + CuO$$
Releted Question 2

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

A. the attack of $$^ - OH$$  at the carbonyl group,
B. the transfer of hydride to the carbonyl group,
C. the abstraction of proton from the carboxylic acid,
D. the deprotonation of $$PhC{H_2}OH.$$
Releted Question 3

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$  is liberated. The $$'C'$$ of $$C{O_2}$$  comes from

A. methyl group
B. carboxylic acid group
C. methylene group
D. bicarbonate
Releted Question 4

Benzoyl chloride is prepared from benzoic acid by

A. $$C{l_2},hv$$
B. $$S{O_2}C{l_2}$$
C. $$SOC{l_2}$$
D. $$C{l_2},{H_2}O$$

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Carboxylic Acid


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