Question
Which one of the following has the regular tetrahedral structure ?
( Atomic nos. : $$B = 5,S = 16,Ni = 28,Xe = 54$$ )
A.
$$BF_4^ - $$
B.
$$S{F_4}$$
C.
$$Xe{F_4}$$
D.
$${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
Answer :
$$BF_4^ - $$
Solution :
$$Xe{F_4}\left( {s{p^3}{d^2}\,{\text{square planar}}} \right),$$
$${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$ $$\left( {ds{p^2}\,\,{\text{square}}\,{\text{planar}}} \right),$$
$$BF_4^ - \left( {s{p^3}\,{\text{tetrahedral}}} \right),\,\,S{F_4}\left( {s{p^3}d\,\,{\text{see}}\,\,{\text{saw}}\,\,{\text{shaped}}} \right)$$