Question
Which of the following reactions follows Markovnikov's rule?
A.
$${C_2}{H_4} + HBr$$
B.
$${C_3}{H_6} + C{l_2}$$
C.
$${C_3}{H_6} + HBr$$
D.
$${C_3}{H_6} + B{r_2}$$
Answer :
$${C_3}{H_6} + HBr$$
Solution :
Markovnikov's rule is followed for addition of $$HX$$ ( $$X =$$ halogen ) on asymmetric alkenes.
\[C{{H}_{3}}CH=C{{H}_{2}}+HBr\to \] \[C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
Br\,\,\,\,
\\
\text{(Major)}
\end{smallmatrix}}{\mathop{-CH-}}\,C{{H}_{3}}+C{{H}_{3}}\] \[\underset{\text{(Minor)}}{\mathop{-C{{H}_{2}}-}}\,C{{H}_{2}}Br\]