Which of the following pairs of metals is purified by van Arkel method ?
A.
$$Ga$$ and $$In$$
B.
$$Zr$$ and $$Ti$$
C.
$$Ag$$ and $$Au$$
D.
$$Ni$$ and $$Fe$$
Answer :
$$Zr$$ and $$Ti$$
Solution :
\[\begin{align}
& Zr\text{ and }Ti\text{ are purified by van Arkel method}\text{.} \\
& \text{Zr}\left( s \right)+2{{I}_{2}}\left( g \right)\xrightarrow{870K}Zr{{I}_{4}}\left( g \right) \\
& Zr{{I}_{4}}\left( g \right)\xrightarrow[\text{Tugsten filament}]{2075K}Zr\left( s \right)+2{{I}_{2}}\left( g \right) \\
& Ti\left( s \right)+2{{I}_{2}}\left( s \right)\xrightarrow{523K}Ti{{I}_{4}}\left( g \right) \\
& Ti{{I}_{4}}\xrightarrow{1700K}\underset{\text{Pure titanium}}{\mathop{Ti\left( s \right)}}\,+2{{I}_{2}}\left( g \right) \\
\end{align}\]
Releted MCQ Question on Inorganic Chemistry >> Ores and Metallurgy