Question

Which of the following orders is not correct for the acidic character?

A. $$C{H_3}C{H_2}CH\left( {Cl} \right)COOH > $$      $$C{H_3}CH\left( {Cl} \right)C{H_2}COOH > $$      $$C{H_2}\left( {Cl} \right)C{H_2}C{H_2}COOH > $$      $$C{H_3}C{H_2}C{H_2}COOH$$
B. $$IC{H_2}COOH < BrC{H_2}COOH$$       $$ < ClC{H_2}COOH < FC{H_2}COOH$$
C. $$CC{l_3}COOH < CHC{l_2}COOH$$       $$ < C{H_2}ClCOOH < C{H_3}COOH$$  
D. $$HCOOH > C{H_3}COOH > $$       $${C_2}{H_5}COOH > {\left( {C{H_3}} \right)_2}CHCOOH$$
Answer :   $$CC{l_3}COOH < CHC{l_2}COOH$$       $$ < C{H_2}ClCOOH < C{H_3}COOH$$
Solution :
The correct order of acidity is $$CC{l_3}COOH > CHC{l_2}COOH$$       $$ > C{H_2}ClCOOH > C{H_3}COOH$$

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

Releted Question 1

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

A. $$Cu$$
B. $$CuO$$
C. $$C{u_2}O$$
D. $$Cu + C{u_2}O + CuO$$
Releted Question 2

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

A. the attack of $$^ - OH$$  at the carbonyl group,
B. the transfer of hydride to the carbonyl group,
C. the abstraction of proton from the carboxylic acid,
D. the deprotonation of $$PhC{H_2}OH.$$
Releted Question 3

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$  is liberated. The $$'C'$$ of $$C{O_2}$$  comes from

A. methyl group
B. carboxylic acid group
C. methylene group
D. bicarbonate
Releted Question 4

Benzoyl chloride is prepared from benzoic acid by

A. $$C{l_2},hv$$
B. $$S{O_2}C{l_2}$$
C. $$SOC{l_2}$$
D. $$C{l_2},{H_2}O$$

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Carboxylic Acid


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