Question
Which of the following is correct ?
A.
$$A$$ on reaction with $$aq.\,KOH$$ gives $$HOC{H_2}C{H_2}COOK$$
B.
$$B$$ can be resolved into $$d–$$ and $$l-$$ forms
C.
Both (A) and (B)
D.
Neither (A) nor (B)
Answer :
Both (A) and (B)
Solution :
The compound $$A$$ is
\[C{{l}_{3}}C.C{{H}_{2}}C{{H}_{2}}Cl\xrightarrow{aq.\,KOH}{{\left( OH \right)}_{3}}C.C{{H}_{2}}C{{H}_{2}}OH\xrightarrow{-2{{H}_{2}}O}HO\,C{{H}_{2}}.C{{H}_{2}}COOK.\]
The compounds $$B$$ is
has chiral centre and can be resolved into $$d-$$ and $$l-$$ form.
The compound $$A$$ is
\[C{{l}_{3}}C.C{{H}_{2}}C{{H}_{2}}Cl\xrightarrow{aq.\,KOH}{{\left( OH \right)}_{3}}C.C{{H}_{2}}C{{H}_{2}}OH\xrightarrow{-2{{H}_{2}}O}HO\,C{{H}_{2}}.C{{H}_{2}}COOK.\]
The compounds $$B$$ is
has chiral centre and can be resolved into $$d-$$ and $$l-$$ form.