When chlorine is passed over dry slaked lime at room temperature, the main reaction product is
A.
$$Ca{\left( {Cl{O_2}} \right)_2}$$
B.
$$CaC{l_2}$$
C.
$$CaOC{l_2}$$
D.
$$Ca{\left( {OCl} \right)_2}$$
Answer :
$$CaOC{l_2}$$
Solution :
When chlorine gas is passed over dry slaked lime, it form bleaching powder i.e. $$CaOC{l_2}.$$
$$Ca{\left( {OH} \right)_2} + C{l_2} \to CaOC{l_2} + {H_2}O$$
Releted MCQ Question on Inorganic Chemistry >> S - Block Elements
Releted Question 1
A substance absorbs $$C{O_2}$$ and voilently reacts with water. The substance is