When a biochemical reaction is carried out in laboratory from outside of human body in the absence of enzyme, the rate of reaction obtained is $${10^{ - 6}}$$ times, then activation energy of the reaction in the presence of enzyme is
A.
$$\frac{6}{{RT}}$$
B.
$$P$$ is required
C.
different from $${E_a}$$ obtained in laboratory
D.
cannot say any things
Answer :
different from $${E_a}$$ obtained in laboratory
Solution :
When a biochemical reaction is carried out in laboratory from outside of human body in the absence of enzyme, then rate of reaction obtained is $${10^{ - 6}}$$ times than activation energy of reaction in the presence of enzyme. It is different from $${E_a}$$ obtained in laboratory because for a given chemical reaction.
$$k = A{e^{ - \frac{{{E_a}}}{{RT}}}}{\text{(arrhenius equation)}}$$
Also activation energy have different value in absence or presence of enzyme.
Releted MCQ Question on Physical Chemistry >> Chemical Kinetics
Releted Question 1
If uranium (mass number 238 and atomic number 92) emits an $$\alpha $$ -particle, the product has mass no. and atomic no.