What volume of oxygen gas $$\left( {{O_2}} \right)$$ measured at $${0^ \circ }C$$ and $$1\,atm,$$ is needed to burn completely $$1L$$ of propane gas $$\left( {{C_3}{H_8}} \right)$$ measured under the same conditions?
A.
$$7L$$
B.
$$6L$$
C.
$$5L$$
D.
$$10L$$
Answer :
$$5L$$
Solution :
$$\mathop {{C_3}{H_8}}\limits_{22.4\,L} + \mathop {5{O_2}}\limits_{5 \times 22.4\,L} \to 3C{O_2} + 4{H_2}O$$
For the combustion of $$22.4L$$ propane, oxygen required $$ = 5 \times 22.4\,L$$
For the combustion of $$1 L$$ of propane
oxygen required $$ = \frac{{5 \times 22.4}}{{22.4}}L = 5L$$
Releted MCQ Question on Physical Chemistry >> Some Basic Concepts in Chemistry
Releted Question 1
$$27 g$$ of $$Al$$ will react completely with how many grams of oxygen?