What is the end product of the following sequences of operations ?
\[Ca{{C}_{2}}\xrightarrow{{{H}_{2}}O}A\xrightarrow[H{{g}^{2+}}]{dil.\,{{H}_{2}}S{{O}_{4}}}B\xrightarrow[{{H}_{2}}]{Ni}C\]
A.
$${\text{Methyl alcohol}}$$
B.
$${\text{Acetaldehyde}}$$
C.
$${C_2}{H_5}OH$$
D.
$${C_2}{H_4}$$
Answer :
$${C_2}{H_5}OH$$
Solution :
\[Ca{{C}_{2}}\xrightarrow{{{H}_{2}}O}\underset{\begin{smallmatrix}
\text{Acetylen e} \\
\left( A \right)
\end{smallmatrix}}{\mathop{HC\equiv CH}}\,\] \[\xrightarrow[H{{g}^{+2}}]{Dil.\,{{H}_{2}}S{{O}_{4}}}\underset{\begin{smallmatrix}
\text{Acetaldehyde} \\
\left( B \right)
\end{smallmatrix}}{\mathop{C{{H}_{3}}CHO}}\,\xrightarrow[{{H}_{2}}]{Ni}\] \[\underset{\left( C \right)}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\]
Releted MCQ Question on Organic Chemistry >> Hydrocarbons (Alkane, Alkene and Alkyne)