Question

What are the correct steps to convert acetaldehyde to acetone?

A. $${C_2}{H_5}MgBr,{H_2}O,{\text{Oxidation}}$$
B. $${\text{Oxidation}},Ca{\left( {OH} \right)_2},{\text{Heat}}$$  
C. $${\text{Reduction, }}KCN{\text{, Hydrolysis }}$$
D. $${\text{Oxidation}},{C_2}{H_5}ONa,{\text{Heat}}$$
Answer :   $${\text{Oxidation}},Ca{\left( {OH} \right)_2},{\text{Heat}}$$
Solution :
Aldehyde and Ketone mcq solution image

Releted MCQ Question on
Organic Chemistry >> Aldehyde and Ketone

Releted Question 1

The reagent with which both acetaldehyde and acetone react easily is

A. Fehling’s reagent
B. Grignard reagent
C. Schiff’s reagent
D. Tollen’s reagent
View Answer
Releted Question 2

The Cannizzaro reaction is not given by

A. trimethylacetaldehye
B. acetaldehyde
C. benzaldehyde
D. formaldehyde
View Answer
Releted Question 3

The compound that will not give iodoform on treatment with alkali and iodine is :

A. acetone
B. ethanol
C. diethyl ketone
D. isopropyl alcohol
View Answer
Releted Question 4

Polarisation of electrons in acrolein may be written as

A. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - \mathop {CH}\limits^{{\delta ^ + }} = O$$
B. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - CH = \mathop O\limits^{{\delta ^ + }} $$
C. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = \mathop {CH}\limits^{{\delta ^ + }} - CH = O$$
D. $$\mathop {C{H_2}}\limits^{{\delta ^ + }} = CH - CH = \mathop O\limits^{{\delta ^ - }} $$
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Aldehyde and Ketone

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Physical ChemistrySome Basic Concepts in ChemistryStoichiometryStates of Matter Solid, Liquid and GasAtomic StructureChemical ThermodynamicsSolutionsSolid StateSurface ChemistryChemical EquilibriumIonic EquilibriumChemical KineticsRedox ReactionElectrochemistryNuclear Chemistry
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