Question
\[\underset{\left( A \right)}{\mathop{{{C}_{16}}{{H}_{16}}}}\,\xrightarrow{{{O}_{3}}}\underset{{{C}_{8}}{{H}_{8}}O}{\mathop{\left( B \right)}}\,\xrightarrow[H{{O}^{-}}/\Delta ]{N{{H}_{2}}-N{{H}_{2}}}\]
\[\underset{\left( A \right)}{\mathop{{{C}_{16}}{{H}_{16}}}}\,\xrightarrow{{{O}_{3}}}\underset{{{C}_{8}}{{H}_{8}}O}{\mathop{\left( B \right)}}\,\xrightarrow[H{{O}^{-}}/\Delta ]{N{{H}_{2}}-N{{H}_{2}}}\] 
reactant $$(A)$$ in this reaction is :
A.
B.
C.
D.
Answer :
Solution :
