Question
The value of the ‘spin only’ magnetic moment for one of the following configurations is 2.84 $$BM.$$ The correct one is
A.
$${d^5}$$ (in strong ligand field)
B.
$${d^3}$$ (in weak as well as in strong fields)
C.
$${d^4}$$ (in weak ligand fields)
D.
$${d^4}$$ (in strong ligand fields)
Answer :
$${d^4}$$ (in strong ligand fields)
Solution :
$${d^5}\, - $$ strong ligand field
$$\mu = n\sqrt {n + 2} = \sqrt 3 = 1.73{\text{BM}}$$
$${d^3} - $$ in weak as well as in strong field
.PNG "Co-ordination Compounds mcq solution image")
$$\mu = \sqrt {3\left( 5 \right)} = \sqrt {15} = 3.87{\text{B}}{\text{.M}}{\text{.}}$$
$${d^4} - $$ in weak ligand field
.PNG "Co-ordination Compounds mcq solution image")
$$\mu = \sqrt {4\left( 8 \right)} = \sqrt {24} = 4.89$$
$${d^4} - $$ in strong ligand field
.PNG "Co-ordination Compounds mcq solution image")
$$\mu = \sqrt {2\left( 4 \right)} = \sqrt 8 = 2.82.$$
$${d^5}\, - $$ strong ligand field
$$\mu = n\sqrt {n + 2} = \sqrt 3 = 1.73{\text{BM}}$$
$${d^3} - $$ in weak as well as in strong field
$$\mu = \sqrt {3\left( 5 \right)} = \sqrt {15} = 3.87{\text{B}}{\text{.M}}{\text{.}}$$
$${d^4} - $$ in weak ligand field
$$\mu = \sqrt {4\left( 8 \right)} = \sqrt {24} = 4.89$$
$${d^4} - $$ in strong ligand field
$$\mu = \sqrt {2\left( 4 \right)} = \sqrt 8 = 2.82.$$