Question
The transition elements have a general electronic configuration.
A.
$$n{s^2}n{p^6}n{d^{1 - 10}}$$
B.
$$\left( {n - 1} \right){d^{1 - 10}},n{s^{0 - 2}},n{p^{0 - 6}}$$
C.
$$\left( {n - 1} \right){d^{1 - 10}},n{s^{1 - 2}}$$
D.
$$n{d^{1 - 10}}n{s^2}$$
Answer :
$$\left( {n - 1} \right){d^{1 - 10}},n{s^{1 - 2}}$$
Solution :
In the transition elements, the $$d$$ - orbitals are successively filled. The general electronic configuration of $$d$$-block is $$\left( {n - 1} \right){d^{1 - 10}}n{s^{1 - 2}}$$
Where $$(n — 1)$$ stands for inner shell and $$d$$ - orbitals may have one to ten electrons and the $$s$$ - orbital of the outermost shell $$(n)$$ may have one or two electrons.