The reaction, $$S{O_2} + C{l_2} \to S{O_2}C{l_2}$$ is exothermic and reversible. A mixture of $$S{O_2}\left( g \right),C{l_2}\left( g \right)$$ and $$S{O_2}C{l_2}\left( l \right)$$ is at equilibrium in a closed container. Now a certain quantity of extra $$S{O_2}$$ is introduced into the container, the volume remaining the same. Which of the following is/are true ?
A.
The pressure inside the container will not change.
B.
The temperature will not change.
C.
The temperature will increase.
D.
The temperature will decrease.
Answer :
The temperature will increase.
Solution :
By addition of $$S{O_2}$$ equilibrium will shift to $$RHS$$ which is exothermic. Hence temperature will increase.
Releted MCQ Question on Physical Chemistry >> Chemical Equilibrium
Releted Question 1
For the reaction : $${H_2}\left( g \right) + {I_2}\left( g \right) \rightleftharpoons 2HI\left( g \right)$$ the equilibrium constant $${K_p}$$ changes with