Question
The reaction conditions leading to the best yields of $${C_2}{H_5}Cl$$ are :
A.
\[{{C}_{2}}{{H}_{6}}\text{(excess)}+C{{l}_{2}}\xrightarrow{UV\,\,\text{light}}\]
B.
\[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow[\text{room}\,\,\text{temperature}]{\text{dark}}\]
C.
\[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\text{(excess)}\xrightarrow{UV\,\,\text{light}}\]
D.
\[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow{UV\,\,\text{light}}\]
Answer :
\[{{C}_{2}}{{H}_{6}}\text{(excess)}+C{{l}_{2}}\xrightarrow{UV\,\,\text{light}}\]
Solution :
\[{{C}_{2}}{{H}_{6}}\text{(excess)}+C{{l}_{2}}\xrightarrow{UV\,\,\text{light}}{{C}_{2}}{{H}_{5}}Cl+HCl\]