The rate constant of the reaction $$A \to B$$ is $$0.6 \times {10^{ - 3}}\,mole$$ per second. If the concentration of $$A$$ is $$5$$ $$M$$ then concentration of $$B$$ after $$20\,\min $$ is
A.
1.08$$\,M$$
B.
3.60$$\,M$$
C.
0.36$$\,M$$
D.
0.72$$\,M$$
Answer :
0.72$$\,M$$
Solution : Key Concept For a zero order reaction unit of rate constant is mole per second. Hence, we can easily calculate concentration of $$B$$ after $$20$$ $$min$$ by the following formula,
$$\eqalign{
& x = Kt \cr
& x = Kt = 0.6 \times {10^{ - 3}} \times 20 \times 60 = 0.72\,M \cr} $$
Releted MCQ Question on Physical Chemistry >> Chemical Kinetics
Releted Question 1
If uranium (mass number 238 and atomic number 92) emits an $$\alpha $$ -particle, the product has mass no. and atomic no.