The $$(R)$$ - and $$(S)$$ - enantiomers of an optically active compound differ in
A.
their solubility in a chiral solvent
B.
their reactivity with a chiral reagent
C.
their optical rotation of plane polarised light
D.
their melting points
Answer :
their optical rotation of plane polarised light
Solution :
$$R$$ and $$S$$ forms of an optically active compound differ in their behaviour towards plane polarised light. The species which rotate the plane polarised
light towards right is called $$R$$ - form ( $$rectus$$ form ) or $$d$$ - form ( $$dextro$$ - form ) and the species which rotate the plane polarised light towards left is known as $$S$$ - form ( $$sinister$$ - form ) or $$l$$ - form ( $$laevo$$ - form ).
Releted MCQ Question on Organic Chemistry >> General Organic Chemistry
Releted Question 1
The bond order of individual carbon-carbon bonds in
benzene is