Question
The products for the following reactions are
The products for the following reactions are
\[\left( \text{i} \right)C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
H\,
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,Br \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{2}}-C{{H}_{3}}\,\,+\] \[alc.\,KOH\to X\]
\[\left( \text{ii} \right)C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}
\end{smallmatrix}}{\mathop{-CH-}}\,CH=C{{H}_{2}}\] \[\xrightarrow{{{O}_{3}}}Y+Z\]
A.
$$X = {\left( {C{H_3}} \right)_2}C = C{H_2},$$ $$Y = C{H_3}C{H_2}CHO,$$ $$Z = C{H_3}C{H_2}CHO$$
B.
$$X = C{H_2} = C{H_2},$$ $$Y = C{H_3}CHO,$$ $$Z = C{H_3}COOH$$
C.
$$X = C{H_3} - CH = CH - C{H_3},$$ \[Y=C{{H}_{3}}\overset{\begin{smallmatrix}
C{{H}_{3}} \\
|\,\,\,\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,CHO,\] $$Z = HCHO$$
D.
$$X = C{H_3} - CH = C{\left( {C{H_3}} \right)_2},$$ $$Y = HCHO,$$ $$Z = C{H_3}CHO$$
Answer :
$$X = C{H_3} - CH = CH - C{H_3},$$ \[Y=C{{H}_{3}}\overset{\begin{smallmatrix}
C{{H}_{3}} \\
|\,\,\,\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,CHO,\] $$Z = HCHO$$
Solution :
\[\left( \text{i} \right)C{{H}_{3}}\underset{\begin{smallmatrix} | \\ H\, \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,Br \\ | \end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{2}}C{{H}_{3}}\xrightarrow{alc.\,KOH}\underset{\begin{smallmatrix} \text{2-Butene} \\ \text{(main product}) \\ 'X' \end{smallmatrix}}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\]
\[\left( \text{i} \right)C{{H}_{3}}\underset{\begin{smallmatrix} | \\ H\, \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,Br \\ | \end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{2}}C{{H}_{3}}\xrightarrow{alc.\,KOH}\underset{\begin{smallmatrix} \text{2-Butene} \\ \text{(main product}) \\ 'X' \end{smallmatrix}}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\]