Question

The principal organic product formed in the reaction, \[C{{H}_{2}}=CH{{\left( C{{H}_{2}} \right)}_{8}}COOH+HBr\xrightarrow{\text{peroxide}}\]         is

A. $$C{H_3}CHBr{\left( {C{H_2}} \right)_8}COOH$$
B. $$C{H_2} = CH{\left( {C{H_2}} \right)_8}COBr$$
C. $$C{H_2}BrC{H_2}{\left( {C{H_2}} \right)_8}COOH$$  
D. $$C{H_2} = CH{\left( {C{H_2}} \right)_7}CHBrCOOH$$
Answer :   $$C{H_2}BrC{H_2}{\left( {C{H_2}} \right)_8}COOH$$
Solution :
Anti Markovnikov's addition

Releted MCQ Question on
Organic Chemistry >> Hydrocarbons (Alkane, Alkene and Alkyne)

Releted Question 1

Marsh gas mainly contains

A. $${C_2}{H_2}$$
B. $$C{H_4}$$
C. $${H_2}S$$
D. $$CO$$
Releted Question 2

Which of the following decolourises alkaline $$KMn{O_4}$$

A. $${C_3}{H_8}$$
B. $${C_2}{H_4}$$
C. $$C{H_4}$$
D. $$CC{l_4}$$
Releted Question 3

The compound with the highest boiling point is

A. $$n $$ - hexane
B. $$n $$ - pentane
C. 2, 2 - dimethylpropane
D. 2 - methylbutane
Releted Question 4

The maximum number of isomers for an alkene with the molecular formula $${C_4}{H_8}$$  is

A. 2
B. 3
C. 4
D. 5

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Hydrocarbons (Alkane, Alkene and Alkyne)


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