Question
The pair of ions having same electronic configuration is _______________.
A.
$$C{r^{3 + }},F{e^{3 + }}$$
B.
$$F{e^{3 + }},M{n^{2 + }}$$
C.
$$F{e^{3 + }},C{o^{3 + }}$$
D.
$$S{c^{3 + }},C{r^{3 + }}$$
Answer :
$$F{e^{3 + }},M{n^{2 + }}$$
Solution :
$$Cr\left( {24} \right):3{d^5}4{s^1},C{r^{3 + }}:3{d^3}$$
$$Fe\left( {26} \right):3{d^6}4{s^2},F{e^{3 + }}:3{d^5};$$ $$Mn\left( {25} \right):3{d^5}4{s^2},M{n^{2 + }}:3{d^5}$$
$$Co\left( {27} \right):3{d^7}4{s^2},C{o^{3 + }}:3{d^6};$$ $$Sc\left( {21} \right):3{d^1}4{s^2},S{c^{3 + }}:3{d^0}$$
Thus, $$F{e^{3 + }}$$ and $$M{n^{2 + }}$$ have same electronic configuration.