The outermost electronic configuration of the most electronegative element is
A.
$$n{s^2}\,n{p^3}$$
B.
$$n{s^2}\,n{p^4}$$
C.
$$n{s^2}\,n{p^5}$$
D.
$$n{s^2}\,n{p^6}$$
Answer :
$$n{s^2}\,n{p^5}$$
Solution :
TIPS/Formulae : The element having highest tendency to accept the electron will be most electronegative element.
Configuration $$n{s^2},\,n{p^5}$$ means it requires only one electron to attain nearest noble gas configuration. So, it will be most electronegative element among given choices.
Releted MCQ Question on Physical Chemistry >> Atomic Structure
Releted Question 1
The number of neutrons in dipositive zinc ion with mass number 70 is