The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number 16 is

Solution :
Suppose the diatomic molecule is $$X.$$
Then, molecular orbital electronic configuration of
$${}_{16}X = \sigma 1{s^2},\mathop \sigma \limits^* 1{s^2},\sigma 2{s^2},\mathop \sigma \limits^* 2{s^2},$$       $$\sigma 2p_z^2,\pi 2p_x^2 \approx \pi 2p_y^2,\mathop \pi \limits^* 2p_x^1 \approx \mathop \pi \limits^* 2p_y^1$$
Due to presence of two unpaired electrons, it shows paramagnetic character.