The major product of the following reaction is :
\[C{{H}_{3}}CH=CHC{{O}_{2}}C{{H}_{3}}\xrightarrow{LiAl{{H}_{4}}}\]
A.
$$C{H_3}C{H_2}C{H_2}C{O_2}C{H_3}$$
B.
$$C{H_3}CH = CHC{H_2}OH$$
C.
$$C{H_3}C{H_2}C{H_2}C{H_2}OH$$
D.
$$C{H_3}C{H_2}C{H_2}CHO$$
Answer :
$$C{H_3}CH = CHC{H_2}OH$$
Solution :
$$LiAl{H_4}$$ reduces esters to alcohols but does not reduce $$C = C.$$
\[C{{H}_{3}}CH=CH-C{{O}_{2}}Me\xrightarrow{LiAl{{H}_{4}}}C{{H}_{3}}CH=CHC{{H}_{2}}OH\]
Releted MCQ Question on Organic Chemistry >> Aldehyde and Ketone
Releted Question 1
The reagent with which both acetaldehyde and acetone react easily is