Question
The ground state electronic configuration of valence shell electrons in nitrogen molecule $$\left( {{N_2}} \right)$$ is written as $$KK,\sigma 2{s^2},\mathop \sigma \limits^* 2{s^2},\sigma 2p_x^2,\pi 2p_y^2$$ $$ \approx \pi 2p_z^2$$
Bond order in nitrogen molecule is
A.
0
B.
1
C.
2
D.
3
Answer :
3
Solution :
$$\eqalign{
& {\text{The }}MO{\text{ configuration of}}\,\,{N_2}\,\,{\text{is}} \cr
& KK,\sigma 2{s^2},\mathop \sigma \limits^ * 2{s^2},\sigma 2p_x^2,\pi 2p_y^2 \approx \pi 2p_z^2 \cr
& {\text{Bond order of}} \cr
& {N_2} = \frac{1}{2}\left[ {{N_b} - {N_a}} \right] \cr
& \,\,\,\,\,\,\,\, = \frac{1}{2}\left[ {8 - 2} \right] \cr
& \,\,\,\,\,\,\,\, = \frac{6}{2} \cr
& \,\,\,\,\,\,\,\, = 3 \cr} $$