The first, second and third ionization enthalpies of an element are 737, 1450 and 7731 $$kJ\,mo{l^{ - 1}}$$ respectively. What will be the formulae of its oxide and chloride?
A.
$${M_2}O,MCl$$
B.
$$MO,MC{l_2}$$
C.
$${M_2}{O_3},MC{l_3}$$
D.
$$M{O_2},MC{l_4}$$
Answer :
$$MO,MC{l_2}$$
Solution :
The element belongs to group 2, and so it forms $$MO$$ and $$MC{l_2}.$$
Releted MCQ Question on Inorganic Chemistry >> Classification of Elements and Periodicity in Properties
Releted Question 1
The correct order of second ionisation potential of carbon, nitrogen, oxygen and fluorine is