Question
The electronic configuration of four elements are given below. Which element does not belong to the same family as others?
A.
$$\left[ {Xe} \right]4{f^{14}},5{d^{10}},6{s^2}$$
B.
$$\left[ {Kr} \right]4{d^{10}},5{s^2}$$
C.
$$\left[ {Ne} \right]3{s^2},3{p^5}$$
D.
$$\left[ {Ar} \right]3{d^{10}},4{s^2}$$
Answer :
$$\left[ {Ne} \right]3{s^2},3{p^5}$$
Solution :
In a family, all elements have same outermost electronic configuration. Since $$\left[ {Ne} \right]3{s^2}3{p^5},$$ chlorine belongs to halogen family while the remaining three are in same group i.e. group 12.
$${}_{80}Hg = \left[ {Xe} \right]4{f^{14}}5{d^{10}}6{s^2}$$
$${}_{48}Cd = \left[ {Kr} \right]4{d^{10}}5{s^2}$$
$${}_{30}Zn = \left[ {Ar} \right]3{d^{10}}4{s^2}$$